The answer to last week’s *Problem of the Week* is that the following definitions represent the factorial of the given non-negative integer:

# Mathematical Definition

Function | Definition | Condition |
---|---|---|

unnamed(n) = | 1 | if n = 0 |

n × unnamed(n – 1) | if n > 0 |

# JavaScript Definition

function unnamed(n) { if(n == 0) return 1; if(n > 0) return n * unnamed(n - 1); }

Although it may have been easy for some people to follow, for those of you who are not familiar with recursion, it may have been a bit difficult. Let’s use the number 4 as an example to step through the process:

- When we pass 4 into unnamed we get the following definition for the output:

`unnamed(4) = 4 × unnamed(4 - 1) = 4 × unnamed(3)`

- Now we have to find the definition for passing 3 into unnamed:

`unnamed(3) = 3 × unnamed(3 - 1) = 3 × unnamed(2)`

- Now we have to find the definition for passing 2 into unnamed:

`unnamed(2) = 2 × unnamed(2 - 1) = 2 × unnamed(1)`

- Now we have to find the definition for passing 1 into unnamed:

`unnamed(1) = 1 × unnamed(1 - 1) = 1 × unnamed(0)`

- Now we have to find the definition for passing 0 into unnamed:

`unnamed(0) = 1`

- Now we go back to step 4 and replace
`unnamed(0)`

with 1:

`unnamed(1) = 1 × 1 = 1`

- Now we go back to step 3 and replace
`unnamed(1)`

with 1:

`unnamed(2) = 2 × 1 = 2`

- Now we go back to step 2 and replace
`unnamed(2)`

with 2:

`unnamed(3) = 3 × 2 = 6`

- Now we go back to step 1 and replace
`unnamed(3)`

with 6:

`unnamed(4) = 4 × 6 = 24`

After stepping through each part of the process, you can more easily see the pattern.

`unnamed(4)`

is really equal to`4 × 3 × 2 × 1 × 1`

`unnamed(3)`

is really equal to`3 × 2 × 1 × 1`

`unnamed(2)`

is really equal to`2 × 1 × 1`

`unnamed(1)`

is really equal to`1 × 1`

`unnamed(0)`

is really equal to`1`

NOTE: The above (`0! = 1`

) is more of a technicality that many people don’t really think about for factorial.

## 1 Comment

## POW – Unnamed Function #1 | Chris West's Blog · February 13, 2012 at 9:30 AM

[…] to this Problem of the Week was posted on February 13, 2012 at 12:00 AM (EST) and can be found here. This entry was posted in Blog, JavaScript, JScript, Math, Problem of the Week and tagged Math, […]